Question Number 52765 by ajfour last updated on 12/Jan/19
Commented by ajfour last updated on 12/Jan/19
$${Q}.\mathrm{52611}\:\:\:\left({part}\:{a}\right) \\ $$
Answered by ajfour last updated on 12/Jan/19
$$\mathrm{2}{T}\mathrm{cos}\:\alpha+{mg}\mathrm{cos}\:\gamma\:=\:{mg} \\ $$$$\mathrm{2}{T}\mathrm{sin}\:\alpha\mathrm{cos}\:\phi\:=\:{mg}\mathrm{sin}\:\gamma \\ $$$$\frac{{l}}{\mathrm{2}}\mathrm{cos}\:\alpha\:=\:{L}\mathrm{cos}\:\gamma \\ $$$$\frac{{l}}{\mathrm{2}}\mathrm{sin}\:\alpha\mathrm{cos}\:\phi\:+{L}\mathrm{sin}\:\gamma\:=\:\frac{{a}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$${and}\:{even} \\ $$$$\frac{{l}}{\mathrm{2}}\mathrm{sin}\:\alpha\mathrm{sin}\:\phi\:=\:\frac{{a}}{\mathrm{2}} \\ $$