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Question Number 52786 by peter frank last updated on 13/Jan/19

Commented by tanmay.chaudhury50@gmail.com last updated on 13/Jan/19

${m w}^{2} r = \frac{G M m}{r^{2}} [M = m a s s o f s u n, m = m a s s o f p l a n e t]$ ${(\frac{2 π}{T})}^{2} = \frac{G M}{r^{3}} [r = d i s t a n c e b e t w e e n p l a n e t a n d s u n]$ $\frac{2 π}{T} = \sqrt{\frac{G M}{r^{3}}} [T = t i m e$ $T = 2 π \sqrt{\frac{r^{3}}{G M}}$ $\frac{T_{s a t u r n}}{T_{e a r t h}} = \sqrt{\frac{r_{s a t u r n}^{3}}{r_{e a r t h}^{3}}}$
	Answered by peter frank last updated on 13/Jan/19

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