If a<∫_0 ^(2π) (1/(10+3 cos x)) dx<b, then the ordered pair (a, b) is


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Question Number 53118 by gunawan last updated on 18/Jan/19

$If a < \int_{0}^{2 π} \frac{1}{10 + 3 \cos x} d x < b, then the$ $ordered pair (a, b) is$
	Answered by tanmay.chaudhury50@gmail.com last updated on 18/Jan/19

	$i a m u s i n g s i m p l e l o g i c . .$ $t h e n i [s h a l l s o l v e i n d e t a i l s$ $w e k n o w c o s x m a x v a l u e = + 1$ $c o s x m i n i m u m v a l u e = - 1$ $s o$ $10 + 3 (1) > 10 + 3 c o s x > 10 + 3 (- 1)$ $13 > 10 + 3 c o s x > 7$ $\frac{1}{13} < \frac{1}{10 + 3 c o s x} < \frac{1}{7}$ $\int_{0}^{2 π} \frac{d x}{13} < \int_{0}^{2 π} \frac{d x}{10 + 3 c o s x} < \int_{0}^{2 π} \frac{d x}{7}$ $\frac{2 π}{13} < \int_{0}^{2 π} \frac{d x}{10 + 3 c o s x} < \frac{2 π}{7}$ $s o a = \frac{2 π}{13} b = \frac{2 π}{7} (\frac{2 π}{13}, \frac{2 π}{7})$
	Commented bygunawan last updated on 19/Jan/19

	$wow thank you Sir$
	Commented bytanmay.chaudhury50@gmail.com last updated on 19/Jan/19

	$m o s t w e l c o m e . . .$
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