Question and Answers Forum

All Questions      Topic List

Mechanics Questions

Previous in All Question      Next in All Question      

Previous in Mechanics      Next in Mechanics      

Question Number 53145 by ajfour last updated on 18/Jan/19

Commented by ajfour last updated on 18/Jan/19

If entire string length is l, find θ  in terms of l,a, r, and R.  Or find l from a,r,R, and θ.

Ifentirestringlengthisl,findθintermsofl,a,r,andR.Orfindlfroma,r,R,andθ.

Commented by tanmay.chaudhury50@gmail.com last updated on 18/Jan/19

Answered by ajfour last updated on 18/Jan/19

l=a+R(π+θ+2cot (θ/2))            +r((π/2)−(θ/2)+tan (θ/2)−(2/(sin θ)))   (my answer).

l=a+R(π+θ+2cotθ2)+r(π2θ2+tanθ22sinθ)(myanswer).

Answered by mr W last updated on 18/Jan/19

Commented by mr W last updated on 18/Jan/19

AB=a  BC^(⌢) =r((π/2)−(θ/2))  CD=HD−HC=(R/(tan (θ/2)))−(r/(tan θ))  DE_(⌣) =R(π+θ)  EF=HE−HF=(R/(tan (θ/2)))−(r/(sin θ))  ⇒l=a+r((π/2)−(θ/2))+(R/(tan (θ/2)))−(r/(tan θ))+R(π+θ)+(R/(tan (θ/2)))−(r/(sin θ))  ⇒l=a+r((π/2)−(θ/2)−(1/(tan θ))−(1/(sin θ)))+R(π+θ+(2/(tan (θ/2))))

AB=aBC=r(π2θ2)CD=HDHC=Rtanθ2rtanθDE=R(π+θ)EF=HEHF=Rtanθ2rsinθl=a+r(π2θ2)+Rtanθ2rtanθ+R(π+θ)+Rtanθ2rsinθl=a+r(π2θ21tanθ1sinθ)+R(π+θ+2tanθ2)

Commented by Otchere Abdullai last updated on 18/Jan/19

thus my prof W

thusmyprofW

Commented by ajfour last updated on 18/Jan/19

Thank you very much Sir.

ThankyouverymuchSir.

Commented by mr W last updated on 18/Jan/19

we had some difference in our results.  do you know the reason sir?

wehadsomedifferenceinourresults.doyouknowthereasonsir?

Commented by ajfour last updated on 18/Jan/19

yes, they are the same,  tan (θ/2)−(1/(2sin (θ/2)cos (θ/2))) = −(1/(tan θ))  hence  tan (θ/2)−(2/(sin θ)) = −(1/(tan θ))−(1/(sin θ))^.

yes,theyarethesame,tanθ212sinθ2cosθ2=1tanθhencetanθ22sinθ=1tanθ1sinθ.

Commented by mr W last updated on 18/Jan/19

thanks sir for the explanation!

thankssirfortheexplanation!

Terms of Service

Privacy Policy

Contact: info@tinkutara.com