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Question Number 53156 by peter frank last updated on 18/Jan/19

Answered by peter frank last updated on 18/Jan/19

$$eV=\frac{1}{2}{mv}^2$$$$\frac{e}{m}=\frac{v^2}{2V}$$$$$$

Answered by peter frank last updated on 18/Jan/19

$$iieV=\frac{1}{2}{mv}^2......\left(i\right)$$$$v=\frac{E}{B}............\left(ii\right)[F_e=F_m=eE=Bev$$$$subeqniiini$$$$\frac{e}{m}=\frac{E^2}{2{VB}^2}$$$$E=\frac{v}{d}$$$$\frac{e}{m}=\frac{E^2}{2{VB}^2}$$$$k=\frac{v}{B^2}$$$${kB}^2=v$$$$B^2\alpha v$$$$$$$$$$$$$$

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