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Question Number 53165 by peter frank last updated on 18/Jan/19

Answered by peter frank last updated on 18/Jan/19

$$halflife\left(T\right)$$$$T=\frac{0.693}{\lambda }.......\left(i\right)$$$$activity=\frac{dN}{dt}=N\lambda .....\left(ii\right)$$$$226g\to 6.023\times {10}^{23}$$$$1g\to N$$$$N=\frac{6.023\times {10}^{23}}{226}$$$$\frac{dN}{dt}=3.67\times {10}^{10}$$$$$$

Answered by peter frank last updated on 18/Jan/19

$$\frac{dN}{dt}=\lambda N$$$$T=\frac{0.693}{\lambda }$$$$N={10}^8$$$$$$$$\left(1\right)N=N_0{e}^{-\lambda t}$$$$\frac{N}{N_0}=fractionremain=-\lambda t$$$$T/t=\frac{0.693}{\lambda }$$$$....$$

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