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Question Number 53273 by ajfour last updated on 19/Jan/19

Commented by ajfour last updated on 19/Jan/19

$$Ifsystemisinequilibrium,find\theta .$$$$rodisLshapedanduniform.$$

Answered by mr W last updated on 19/Jan/19

$$\frac{aMg}{a+b}\times \frac{a\sin \theta }{2}+\frac{bMg}{a+b}\times (a\sin \theta -\frac{b\cos \theta }{2})+mg(a\sin \theta -b\cos \theta )=0$$$$\frac{a}{a+b}\times a\tan \theta +\frac{b}{a+b}\times (2a\tan \theta -b)+\frac{2m}{M}(a\tan \theta -b)=0$$$$(\frac{a^2+2ab}{a+b}+\frac{2ma}{M})\tan \theta =\frac{b^2}{a+b}+\frac{2mb}{M}$$$$\Rightarrow \theta ={\tan }^{-1}\frac{b[bM+2(a+b)m]}{a[(a+2b)M+2(a+b)m]}$$

Commented by ajfour last updated on 20/Jan/19

$$ThankyouSir,answerispresented$$$$thebestway.$$

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