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Question Number 53324 by 0955083339 last updated on 20/Jan/19
If4a+5b+9c=36and7a+9b+17c=66,thena+b+c=_____.
Answered by Kunal12588 last updated on 21/Jan/19
leta+b+c=k4a+4b+4c+b+5c=36⇒4k+(b+5c)=36(1)7a+7b+7c+2b+10c=66⇒7k+2(b+5c)=66(2)letb+5c=h4k+h=36[multiplyby2]8k+2h=727k+2h=66⇒k=a+b+c=72−66=6
Commented by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19
excellent...
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