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Question Number 53328 by Tawa1 last updated on 20/Jan/19

Commented by maxmathsup by imad last updated on 20/Jan/19

$$f\left(x\right)=tanxsinx=\frac{{sin}^{2}x}{cosx}.$$

Commented by Tawa1 last updated on 20/Jan/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Answered by tanmay.chaudhury50@gmail.com last updated on 20/Jan/19

$$f\left(x\right)=tan(\pi +x)cos(x-\frac{\pi }{2})$$$$=\left(tanx\right)\times sinx$$$$$$$$=\frac{{sin}^{2}x}{cosx}$$

Commented by Tawa1 last updated on 20/Jan/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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