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Question Number 53447 by rajeshghorai130@gmail.com last updated on 22/Jan/19

Answered by tanmay.chaudhury50@gmail.com last updated on 22/Jan/19

a=sin^2 x b=sin^2 y (((1−a)^2 )/(1−b))+(a^2 /b)=1 b−2ab+a^2 b+a^2 −a^2 b=b−b^2 b−2ab+a^2 −b+b^2 =0 (a−b)^2 =0 a=b sin^2 x=sin^2 y [so x=y] ((cos^4 y)/(cos^2 x))+((sin^4 y)/(sin^2 x)) =((cos^4 x)/(cos^2 x))+((sin^4 x)/(sin^2 x)) =cos^2 x+sin^2 x =1 proved

a=sin2xb=sin2y(1−a)21−b+a2b=1b−2ab+a2b+a2−a2b=b−b2b−2ab+a2−b+b2=0(a−b)2=0a=bsin2x=sin2y[sox=y]cos4ycos2x+sin4ysin2x=cos4xcos2x+sin4xsin2x=cos2x+sin2x=1proved

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