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Question Number 53522 by 0955083339 last updated on 22/Jan/19

Cost of  2 pencils and  3 erasers is Rs.18,  while the cost of  1  pencil and  2 erasers  is Rs. 11. Find the cost of each pencil.

$$\mathrm{Cost}\:\mathrm{of}\:\:\mathrm{2}\:\mathrm{pencils}\:\mathrm{and}\:\:\mathrm{3}\:\mathrm{erasers}\:\mathrm{is}\:\mathrm{Rs}.\mathrm{18}, \\ $$$$\mathrm{while}\:\mathrm{the}\:\mathrm{cost}\:\mathrm{of}\:\:\mathrm{1}\:\:\mathrm{pencil}\:\mathrm{and}\:\:\mathrm{2}\:\mathrm{erasers} \\ $$$$\mathrm{is}\:\mathrm{Rs}.\:\mathrm{11}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{cost}\:\mathrm{of}\:\mathrm{each}\:\mathrm{pencil}. \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jan/19

2p+3er=18×2  1p+2er=11×3  4p+6er=36  3p+6er=33  substructing  p=Rs3  3+2er=11  2er=11−3  er=4  cost of each pencil=Rs 3  cost of each eraser=Rs 4

$$\mathrm{2}{p}+\mathrm{3}{er}=\mathrm{18}×\mathrm{2} \\ $$$$\mathrm{1}{p}+\mathrm{2}{er}=\mathrm{11}×\mathrm{3} \\ $$$$\mathrm{4}{p}+\mathrm{6}{er}=\mathrm{36} \\ $$$$\mathrm{3}{p}+\mathrm{6}{er}=\mathrm{33} \\ $$$${substructing} \\ $$$${p}={Rs}\mathrm{3} \\ $$$$\mathrm{3}+\mathrm{2}{er}=\mathrm{11} \\ $$$$\mathrm{2}{er}=\mathrm{11}−\mathrm{3} \\ $$$${er}=\mathrm{4} \\ $$$${cost}\:{of}\:{each}\:{pencil}={Rs}\:\mathrm{3} \\ $$$${cost}\:{of}\:{each}\:{eraser}={Rs}\:\mathrm{4} \\ $$

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