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Question Number 53522 by 0955083339 last updated on 22/Jan/19

$$\mathrm{Cost}\mathrm{of}2\mathrm{pencils}\mathrm{and}3\mathrm{erasers}\mathrm{is}\mathrm{Rs}.18,$$$$\mathrm{while}\mathrm{the}\mathrm{cost}\mathrm{of}1\mathrm{pencil}\mathrm{and}2\mathrm{erasers}$$$$\mathrm{is}\mathrm{Rs}.11.\mathrm{Find}\mathrm{the}\mathrm{cost}\mathrm{of}\mathrm{each}\mathrm{pencil}.$$

Answered by tanmay.chaudhury50@gmail.com last updated on 23/Jan/19

$$2p+3er=18\times 2$$$$1p+2er=11\times 3$$$$4p+6er=36$$$$3p+6er=33$$$$substructing$$$$p=Rs3$$$$3+2er=11$$$$2er=11-3$$$$er=4$$$$costofeachpencil=Rs3$$$$costofeacheraser=Rs4$$

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