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Question Number 537 by kth last updated on 25/Jan/15
∫45x−2(x2−4x+3)3dx
Answered by Vishal last updated on 25/Jan/15
letx2−4x+3=tthen(x−2)dx=dt2⇒∫t1t2dt2(t)3=12∫38t−3dt=−14[1t2]38⇒−14[164−19]=−14(−55576)=552304
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