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Question Number 53727 by Tawa1 last updated on 25/Jan/19

	Answered by Kunal12588 last updated on 25/Jan/19

	$j u s t t r y i n g$ $T_{1}, T_{2}, T_{3}, T_{4} - l o w e r c a b l e s$ $T_{1} = T_{2} = T_{3} = T_{4} = k (i d e n t i c a l c a b l e s)$ $\frac{1}{2} (\sqrt{2^{2} + 0 . 5^{2}}) = h$ ${t a n}^{- 1} (2 / h) = ϕ$ $4 k c o s ϕ - m g = 0$ $4 k c o s ϕ = w$ $k = \frac{4.9}{4 c o s ϕ}$ $T_{u p p e r} = 4 k c o s ϕ [n o t s o l v e d i t b c u z i t h i n k i t s w r o n g]$ $p l e a s e r e p o r t w i t h a n s w e r$
	Commented by Tawa1 last updated on 25/Jan/19

	$God bless you sir$
	Answered by tanmay.chaudhury50@gmail.com last updated on 25/Jan/19

	$d i m e n s i o n o f b o x = l \times b \times h$ $d i a g o n a l = \sqrt{l^{2} + b^{2}} =$ $t a n θ = \frac{h}{\frac{\sqrt{l^{2} + b^{2}}}{2}} = \frac{2 h}{\sqrt{l^{2} + b^{2}}}$ $4 T_{l o w e r c a b l e} s i n θ = m g$ $T_{l o w e r c a b l e} = \frac{m g}{4 s i n θ}$ $T_{u p p e r} = m g$
	Commented by Tawa1 last updated on 25/Jan/19

	$God bless you sir . you can help me complete it if correct sir .$
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