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Question Number 53907 by peter frank last updated on 27/Jan/19

Answered by ajfour last updated on 27/Jan/19

$$y={ax}^2$$$$0.1={\left(\frac{5}{2}\right)}^{2}a\Rightarrow a=\frac{2}{125}$$$$y=\frac{2}{125}{x}^2$$$$Noneedofabovecalculations$$$$y_{?}\approx 4m.$$

Commented by peter frank last updated on 27/Jan/19

$$thankyousir$$

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