All Questions Topic List
UNKNOWN Questions
Previous in All Question Next in All Question
Previous in UNKNOWN Next in UNKNOWN
Question Number 54034 by qw last updated on 28/Jan/19
Iff(x)=f(a+b−x),then∫baxf(x)dx=
Commented by maxmathsup by imad last updated on 28/Jan/19
∫abxf(x)dx=∫abxf(a+b−x)dxchangementa+b−x=tgive∫abxf(x)dx=∫ab(a+b−t)f(t)dt=∫ab(a+b)f(t)−∫abtf(t)dt⇒2∫abxf(x)=(a+b)∫abf(x)⇒∫abxf(x)dx=a+b2∫abf(x)dx.
Terms of Service
Privacy Policy
Contact: info@tinkutara.com