Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 54156 by Tawa1 last updated on 30/Jan/19

$$\mathrm{Please}\mathrm{sirs},\mathrm{How}\mathrm{is},-\cot \left(\alpha \right)=\tan (\frac{1}{2}\pi +\alpha )????$$

Commented by turbo msup by abdo last updated on 30/Jan/19

$$tan(\frac{\pi }{2}+\alpha )=\frac{sin(\frac{\pi }{2}+\alpha )}{cos(\frac{\pi }{2}+\alpha )}$$$$=\frac{cos\alpha }{-sin\alpha }=-\frac{1}{tan\alpha }=-cotan\alpha .$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com