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Question Number 5425 by love math last updated on 14/May/16
∫13ln(3x−2)dx
Answered by nchejane last updated on 14/May/16
[xln(3x−2)]13−3∫13xdx3x−2=[3ln(7)−3∫13[13+2313x−2]dx=3ln(7)−[x+23ln(3x−2)]13=3ln(7)−2−23ln(7)=73ln(7)−2
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