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Question Number 54466 by 05051993 last updated on 04/Feb/19

$$\frac{6+\sqrt{{\left(6\right)}^2-4\left(1\right)\left(10\right)}}{2}$$$$$$

Commented by Tawa1 last updated on 04/Feb/19

$$=\frac{6+\sqrt{36-40}}{2}$$$$=\frac{6+\sqrt{-4}}{2}$$$$=\frac{6+\sqrt{-1\times 4}}{2}$$$$=\frac{6+\sqrt{-1}\times \sqrt{4}}{2}\mathrm{Where},\sqrt{-1}=\mathrm{i}$$$$=\frac{6+2\mathrm{i}}{2}$$$$=\frac{6}{2}+\frac{2\mathrm{i}}{2}$$$$=3+\mathrm{i}$$

Answered by Prithwish sen last updated on 04/Feb/19

$$=3+\mathrm{i}(\mathrm{where}\mathrm{i}=\sqrt{-1}$$

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