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Question Number 54504 by afachri last updated on 05/Feb/19

please,Sir.   Would u explain to me how ?  if  f((x/(x − 1)))  +  2f(((x − 1)/x))  =  (x/(x − 1))   ,  then  f(x)  is ....

$$\boldsymbol{\mathrm{please}},\boldsymbol{\mathrm{Sir}}.\:\:\:\boldsymbol{\mathrm{Would}}\:\boldsymbol{\mathrm{u}}\:\boldsymbol{\mathrm{explain}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{how}}\:? \\ $$$$\boldsymbol{\mathrm{if}}\:\:\boldsymbol{{f}}\left(\frac{\boldsymbol{{x}}}{\boldsymbol{{x}}\:−\:\mathrm{1}}\right)\:\:+\:\:\mathrm{2}\boldsymbol{{f}}\left(\frac{\boldsymbol{{x}}\:−\:\mathrm{1}}{\boldsymbol{{x}}}\right)\:\:=\:\:\frac{\boldsymbol{{x}}}{\boldsymbol{{x}}\:−\:\mathrm{1}}\:\:\:, \\ $$$$\boldsymbol{\mathrm{then}}\:\:\boldsymbol{{f}}\left(\boldsymbol{{x}}\right)\:\:\boldsymbol{\mathrm{is}}\:.... \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 05/Feb/19

f(a)+2f((1/a))=a ×2  f((1/a))+2f(a)=(1/a)  ×1    2f(a)+4f((1/a))=2a  2f(a)+f((1/a))=(1/a)  so 3f((1/a))=2a−(1/a)  3f((1/a))=((2/(1/a))−(1/a))  f((1/a))=(1/3)((2/(1/a))−(1/a))  f(x)=(1/3)((2/x)−x)

$${f}\left({a}\right)+\mathrm{2}{f}\left(\frac{\mathrm{1}}{{a}}\right)={a}\:×\mathrm{2} \\ $$$${f}\left(\frac{\mathrm{1}}{{a}}\right)+\mathrm{2}{f}\left({a}\right)=\frac{\mathrm{1}}{{a}}\:\:×\mathrm{1} \\ $$$$ \\ $$$$\mathrm{2}{f}\left({a}\right)+\mathrm{4}{f}\left(\frac{\mathrm{1}}{{a}}\right)=\mathrm{2}{a} \\ $$$$\mathrm{2}{f}\left({a}\right)+{f}\left(\frac{\mathrm{1}}{{a}}\right)=\frac{\mathrm{1}}{{a}} \\ $$$${so}\:\mathrm{3}{f}\left(\frac{\mathrm{1}}{{a}}\right)=\mathrm{2}{a}−\frac{\mathrm{1}}{{a}} \\ $$$$\mathrm{3}{f}\left(\frac{\mathrm{1}}{{a}}\right)=\left(\frac{\mathrm{2}}{\frac{\mathrm{1}}{{a}}}−\frac{\mathrm{1}}{{a}}\right) \\ $$$${f}\left(\frac{\mathrm{1}}{{a}}\right)=\frac{\mathrm{1}}{\mathrm{3}}\left(\frac{\mathrm{2}}{\frac{\mathrm{1}}{{a}}}−\frac{\mathrm{1}}{{a}}\right) \\ $$$${f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{3}}\left(\frac{\mathrm{2}}{{x}}−{x}\right) \\ $$

Commented by afachri last updated on 05/Feb/19

ahaaa. i was curious and getting stuck   how to solve it. instead it′s simple.  Thank You so much Mr Tanmay.

$${ahaaa}.\:{i}\:{was}\:{curious}\:{and}\:{getting}\:{stuck}\: \\ $$$${how}\:{to}\:{solve}\:{it}.\:{instead}\:{it}'{s}\:{simple}. \\ $$$${Thank}\:{You}\:{so}\:{much}\:{Mr}\:{Tanmay}.\: \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 05/Feb/19

most welcome sir...

$${most}\:{welcome}\:{sir}... \\ $$

Commented by Joel578 last updated on 06/Feb/19

Mr. Afachri, are u from Indonesia?

$$\mathrm{Mr}.\:\mathrm{Afachri},\:\mathrm{are}\:\mathrm{u}\:\mathrm{from}\:\mathrm{Indonesia}? \\ $$

Commented by afachri last updated on 08/Feb/19

yes i am Mr Joel. Are you ??

$$\mathrm{yes}\:\mathrm{i}\:\mathrm{am}\:\boldsymbol{\mathrm{M}}{r}\:\boldsymbol{\mathrm{Joel}}.\:\boldsymbol{\mathrm{A}}{re}\:{you}\:?? \\ $$

Commented by Joel578 last updated on 08/Feb/19

wah sama, hehehe

$$\mathrm{wah}\:\mathrm{sama},\:\mathrm{hehehe} \\ $$

Commented by afachri last updated on 08/Feb/19

aseekk ketemu sama sama di sini.   mohon bimbingannya. Main brainly  juga ??

$${aseekk}\:{ketemu}\:{sama}\:{sama}\:{di}\:{sini}.\: \\ $$$${mohon}\:{bimbingannya}.\:{Main}\:{brainly} \\ $$$${juga}\:?? \\ $$$$ \\ $$

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