(√(1−x^2 +))(√(1−y^2 ))=a(x−y) (dy/dx)=(√((1−y^2 )/(1−x^2 ))) without solve put x=sinθand y=sinφ direct solve


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Question Number 54745 by arvinddayama00@gmail.com last updated on 10/Feb/19

$\sqrt{1 - x^{2} +} \sqrt{1 - y^{2}} = a (x - y)$ $\frac{d y}{d x} = \sqrt{\frac{1 - y^{2}}{1 - x^{2}}}$ $w i t h o u t s o l v e p u t x = s i n θ a n d$ $y = s i n ϕ$ $d i r e c t s o l v e$
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