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Question Number 54821 by Abdo msup. last updated on 12/Feb/19
findlimn→+∞∫0narctan(nx)n2+x2dx
Commented by maxmathsup by imad last updated on 13/Feb/19
letAn=∫0narctan(nx)n2+x2dx⇒An=x=nt∫01arctan(n2t)n2(1+t2)ndt=1n∫01arctan(n2t)1+t2dtbutlimn→+∞∫01arctan(n2t)1+t2dt=π2∫01dt1+t2=π2π4=π28andlimn→+∞1n=0⇒limn→+∞An=0.
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