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Question Number 54825 by Tawa1 last updated on 12/Feb/19

Answered by tanmay.chaudhury50@gmail.com last updated on 12/Feb/19

$$v_0=volumeofglassbottlebeforeheating$$$$v_0(1+{\gamma }_g△T)=volumeofglassbottleafterheating$$$$v_0(1+{\gamma }_m△T)=volumeofmercuryafterheating$$$$m_e=massofmercuryexpelled$$$$d_0=densityofmercurybeforeheating$$$$massofmercuryremainsame...$$$$v_0(1+{\gamma }_m△T)\left(\frac{d_0}{1+{\gamma }_m△T}\right)=v_0(1+{\gamma }_g△T)\times \left(\frac{d_0}{1+{\gamma }_m△T}\right)+m_e$$$$v_0\left(\frac{d_0}{1+{\gamma }_m△T}\right)({\gamma }_m-{\gamma }_g)△T=m_e$$$$\left(\frac{m_0}{1+{\gamma }_m△T}\right)({\gamma }_m-{\gamma }_g)△T=m_e$$$$m_0=\frac{m_e(1+{\gamma }_m△T)}{({\gamma }_m-{\gamma }_g)△T}$$$$m_0=\frac{m_e(1+{\gamma }_m△T)}{({\gamma }_m-3{\alpha }_g)△T}$$$$requiredansweris$$$$m_0-m_e$$$$m_e[\frac{1+{\gamma }_m△T}{({\gamma }_m-3{\alpha }_g)△T}-1]$$$$plscheck...andputvalues...$$$$$$$$$$

Commented by Tawa1 last updated on 13/Feb/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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