Question Number 54868 by peter frank last updated on 13/Feb/19
Commented by prakash jain last updated on 14/Feb/19
$$\alpha\centerdot\frac{\mathrm{1}}{\alpha}=\frac{\mathrm{10}}{\mathrm{3}{k}+\mathrm{4}}\Rightarrow{k}=\mathrm{2} \\ $$
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Question Number 54868 by peter frank last updated on 13/Feb/19 | ||
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Commented by prakash jain last updated on 14/Feb/19 | ||
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$$\alpha\centerdot\frac{\mathrm{1}}{\alpha}=\frac{\mathrm{10}}{\mathrm{3}{k}+\mathrm{4}}\Rightarrow{k}=\mathrm{2} \\ $$ | ||