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Question Number 54869 by peter frank last updated on 13/Feb/19

Answered by $@ty@m last updated on 13/Feb/19

Given β=(1/α) ⇒αβ=1 ⇒((10)/(3k+4))=1 ⇒3k+4=10 ⇒k=2

Givenβ=1α⇒αβ=1⇒103k+4=1⇒3k+4=10⇒k=2

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