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Question Number 54995 by peter frank last updated on 15/Feb/19

∫ ((x^3 +x^2 ))^(1/3)  dx

x3+x23dx

Commented by MJS last updated on 16/Feb/19

I can solve this but it′s a lot of typing work  if you need it urgently I will post it

IcansolvethisbutitsalotoftypingworkifyouneediturgentlyIwillpostit

Commented by peter frank last updated on 16/Feb/19

please sir post it....it will   helpful to me and others

pleasesirpostit....itwillhelpfultomeandothers

Commented by MJS last updated on 16/Feb/19

ok might take some time

okmighttakesometime

Answered by tanmay.chaudhury50@gmail.com last updated on 16/Feb/19

∫x^(2/3) (1+x)^(1/3) dx  ∫x^(2/3) [1+(1/3)x+(1/3)((1/3)−1)(x^2 /(2!))+(1/3)((1/3)−1)((1/3)−2)(x^3 /(3!))+...]dx  ∫x^(2/3) +(1/3)x^(5/3) +(1/3)((1/3)−1)x^(8/3) ×(1/(2!))+(1/3)((1/3)−1)((1/3)−2)(x^((11)/3) /(3!))+...]dx  so in the form of...  ∫x^(2/3) +a_1 x^(5/3) +a_2 x^(8/3) +a_3 x^((11)/3) +...dx  (x^(5/3) /(5/3))+a_1 ×(x^(8/3) /(8/3))+a_2 (x^((11)/3) /((11)/3))+....

x23(1+x)13dxx23[1+13x+13(131)x22!+13(131)(132)x33!+...]dxx23+13x53+13(131)x83×12!+13(131)(132)x1133!+...]dxsointheformof...x23+a1x53+a2x83+a3x113+...dxx5353+a1×x8383+a2x113113+....

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