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Question Number 55006 by naka3546 last updated on 16/Feb/19

Answered by MJS last updated on 16/Feb/19

$$x=y=z=1\mathrm{is}\mathrm{a}\mathrm{solution}$$$$\left(1\right)\Rightarrow z=\frac{x+y-xy}{x+y-1}$$$$\left(2\right)\Rightarrow y=-\frac{x-3}{2}\pm \frac{(x-1)\sqrt{3}}{2}\mathrm{i}\Rightarrow z=-\frac{x-3}{2}\mp \frac{(x-1)\sqrt{3}}{2}\mathrm{i}$$$$2\mathrm{equations}\mathrm{in}3\mathrm{variables}\mathrm{give}\mathrm{a}\mathrm{parametric}$$$$\mathrm{solution}$$

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