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Question Number 55051 by maxmathsup by imad last updated on 16/Feb/19
calculatelimn→+∞∫01dx1+x+x2+...+xn
Commented by maxmathsup by imad last updated on 24/Feb/19
letIn=∫01dx1+x+x2+...+xn⇒In=∫01dx1−xn+11−x=∫011−x1−xn+1dx=∫R1−x1−xn+1χ]0,1[(x)dxthesequenceoffunctionfn(x)=1−x1−xn+1χ]0,1[(x)convergestof(x)=1−x⇒imn→+∞In=∫01(1−x)dx=[x−x22]01=1−12=12
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