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Question Number 55072 by peter frank last updated on 17/Feb/19

Commented by mr W last updated on 17/Feb/19

(ax+by)(bx−ay)=0 abx^2 −(a^2 −b^2 )xy−aby^2 =0 ⇒x^2 −y^2 −((a^2 −b^2 )/(ab))xy=0

(ax+by)(bx−ay)=0abx2−(a2−b2)xy−aby2=0⇒x2−y2−a2−b2abxy=0

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