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Question Number 55104 by Gulay last updated on 17/Feb/19

Commented by Gulay last updated on 17/Feb/19

$$\mathrm{sir}\mathrm{could}\mathrm{you}\mathrm{help}\mathrm{me}???$$$$\mathrm{plz}\mathrm{help}\mathrm{me}\mathrm{sir}$$

Commented by math1967 last updated on 17/Feb/19

$$a^{{log}_{a}x}=x\therefore 2^{{log}_{2}8}=8$$$$3^{{log}_{3}9}=9$$$$$$

Commented by Gulay last updated on 18/Feb/19

$$\mathrm{thank}\mathrm{you}\mathrm{sir}$$

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