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Question Number 55166 by Gulay last updated on 18/Feb/19

Answered by kaivan.ahmadi last updated on 18/Feb/19

$$3^{1+{log}_{3}2}=3^{{log}_{3}3+{log}_{3}2}=3^{{log}_{3}6}=6$$$$and$$$$2^{3{log}_{2}5}=2^{{log}_2{5}^3}=5^3=125$$$$and$$$$4^{{log}_{2}3}={\left(2^2\right)}^{{log}_{2}3}=2^{2{log}_{2}3}=2^{{log}_2{3}^2}=3^2=9$$

Commented by Gulay last updated on 19/Feb/19

$$\mathrm{thank}\mathrm{you}\mathrm{sir}$$$$$$

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