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Question Number 55171 by Tawa1 last updated on 18/Feb/19

Commented by Tawa1 last updated on 19/Feb/19

God bless you sir. I will use your answer.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{will}\:\mathrm{use}\:\mathrm{your}\:\mathrm{answer}. \\ $$

Commented by Kunal12588 last updated on 19/Feb/19

sir i get  T=((2u tanα)/g)  and R=((u cos2α T)/(cosα))  but after putting the value of T to get R  R=((2u^2 tanα)/g)×((cos 2α)/(cos α))  pls report with answer

$${sir}\:{i}\:{get} \\ $$$${T}=\frac{\mathrm{2}{u}\:{tan}\alpha}{{g}} \\ $$$${and}\:{R}=\frac{{u}\:{cos}\mathrm{2}\alpha\:{T}}{{cos}\alpha} \\ $$$${but}\:{after}\:{putting}\:{the}\:{value}\:{of}\:{T}\:{to}\:{get}\:{R} \\ $$$${R}=\frac{\mathrm{2}{u}^{\mathrm{2}} {tan}\alpha}{{g}}×\frac{{cos}\:\mathrm{2}\alpha}{{cos}\:\alpha} \\ $$$${pls}\:{report}\:{with}\:{answer} \\ $$

Commented by Kunal12588 last updated on 19/Feb/19

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