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Question Number 55526 by alex26 last updated on 26/Feb/19
If∫4−1f(x)dx=4and∫42(3−f(x))dx=7,then∫−12f(x)dx=
Commented by mr W last updated on 26/Feb/19
∫42(3−f(x))dx=7⇒3(4−2)−∫42f(x)dx=7⇒∫42f(x)dx=−1∫4−1f(x)dx=4⇒∫2−1f(x)dx+∫42f(x)dx=4⇒∫2−1f(x)dx−1=4⇒∫2−1f(x)dx=5⇒−∫−12f(x)dx=5⇒∫−12f(x)dx=−5
Answered by tanmay.chaudhury50@gmail.com last updated on 26/Feb/19
∫f(x)dx=g(x)+c∫−14f(x)dxg(4)−g(−1)=4.....(1)eqn∫24{3−f(x)}dx∣3x−g(x)∣243×4−g(4)−3×2+g(2)6−g(4)+g(2)=7.....(2)eqnaddeqn1andean26+g(2)−g(−1)=11g(2)−g(−1)=5g(−1)−g(2)=−5so∫2−1f(x)dx=−5plscheck...
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