A dish of mixed nut contains cashew and peanut . then two ounces of peanut are added to the dish making the new mixture of 20% cashew. Sara like cashew so she added 2 ounces of them to the dish. The mixture in the dish is now 33.33%. Cashews. what percentage of the origional mixture of nut was cashew? this was the correct question please help


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Question Number 55534 by otchereabdullai@gmail.com last updated on 26/Feb/19

$A d i s h o f m i x e d n u t c o n t a i n s c a s h e w$ $a n d p e a n u t . t h e n t w o o u n c e s o f$ $p e a n u t a r e a d d e d t o t h e d i s h m a k i n g$ $t h e n e w m i x t u r e o f 20 % c a s h e w .$ $S a r a l i k e c a s h e w s o s h e a d d e d$ $2 o u n c e s o f t h e m t o t h e d i s h . T h e$ $m i x t u r e i n t h e d i s h i s n o w 33 . 33 % .$ $C a s h e w s . w h a t p e r c e n t a g e o f t h e$ $o r i g i o n a l m i x t u r e o f n u t w a s$ $c a s h e w ? t h i s w a s t h e c o r r e c t q u e s t i o n$ $p l e a s e h e l p$
	Answered by MJS last updated on 26/Feb/19

	$c ounces of cashews and p ounces of peanuts$ $\frac{c}{c + p + 2} = \frac{1}{5} \Rightarrow p = 4 c - 2$ $\frac{c + 2}{c + p + 4} = \frac{1}{3} \Rightarrow \frac{c + 2}{5 c + 2} = \frac{1}{3} \Rightarrow c = 2 \land p = 6$ $\frac{2}{2 + 6} = \frac{1}{4} \Rightarrow 25 % cashews in the original mix$
	Commented by otchereabdullai@gmail.com last updated on 26/Feb/19

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