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Question Number 55560 by Tawa1 last updated on 26/Feb/19

	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Feb/19
	$x=tana ∫_0 ^(π/2) ((sec^6 a×sec^2 ada)/((tan^4 a+sec^2 a)^(5/2) )) ∫_0 ^(π/2) (da/(cos^8 a{((sin^4 a)/(cos^4 a))+(1/(cos^2 a))}^(5/2) )) ∫_0 ^(π/2) (da/(cos^8 a{((sin^4 a+cos^2 a)/(cos^4 a))}^(5/2) )) ∫_0 ^(π/2) ((cos^(10) a)/(cos^8 a(sin^4 a+cos^2 a)^(5/2) ))da ∫_0 ^(π/2) ((cos^2 ada)/((sin^4 a+cos^2 a)^(5/2) ))da wait...$
	$x = t a n a$ $\int_{0}^{\frac{π}{2}} \frac{{s e c}^{6} a \times {s e c}^{2} a d a}{{({t a n}^{4} a + {s e c}^{2} a)}^{\frac{5}{2}}}$ $\int_{0}^{\frac{π}{2}} \frac{d a}{{c o s}^{8} a {\frac{{s i n}^{4} a}{{c o s}^{4} a} + \frac{1}{{c o s}^{2} a}}^{\frac{5}{2}}}$ $\int_{0}^{\frac{π}{2}} \frac{d a}{{c o s}^{8} a {\frac{{s i n}^{4} a + {c o s}^{2} a}{{c o s}^{4} a}}^{\frac{5}{2}}}$ $\int_{0}^{\frac{π}{2}} \frac{{c o s}^{10} a}{{c o s}^{8} a {({s i n}^{4} a + {c o s}^{2} a)}^{\frac{5}{2}}} d a$ $\int_{0}^{\frac{π}{2}} \frac{{c o s}^{2} a d a}{{({s i n}^{4} a + {c o s}^{2} a)}^{\frac{5}{2}}} d a$ $w a i t . . .$
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