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Question Number 55637 by gunawan last updated on 01/Mar/19
Valueoflimn→∞n∫012xnx+x2n+1dx=..
Answered by tanmay.chaudhury50@gmail.com last updated on 01/Mar/19
∫012xn−11+(xn)2dx2n×∫01d(xn)1+(xn)22n×∣tan−1(xn)∣012n×π4limn→∞π2n×n→π2
Answered by tm888 last updated on 01/Mar/19
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