Is true or not that 4181 is the only one Fibonacci′s number with no prime factor which is also a Fibonacci′s number?


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Question Number 55701 by mathaddicted last updated on 02/Mar/19

$I s t r u e o r n o t t h a t 4181 i s t h e o n l y o n e$ ${F i b o n a c c i}^{'} s n u m b e r w i t h n o p r i m e f a c t o r$ $w h i c h i s a l s o a {F i b o n a c c i}^{'} s n u m b e r ?$
Commented by MJS last updated on 03/Mar/19

$1346269 = 557 \times 2417$ $24157817 = 73 \times 149 \times 2221$ $. . .$
	Answered by Kunal12588 last updated on 03/Mar/19

	Commented by Kunal12588 last updated on 03/Mar/19

	Commented by Kunal12588 last updated on 03/Mar/19

	$4181 i s t h e 20 t h t e r m o f t h e f i b o n a c c i s e r i e s$ $i f s t a r t e d w i t h 0 . e l s e i t s 19 t h t e r m$ $4181 = 37 \times 113 s o i t s f a c t o r s a r e 1, 37, 113, 4181$ $e x c l u d i n g 1 a n d 4181 i t s e l f$ $f a c t o r s o f 4181 a r e 37, 113 t h o s e w e r e n o t$ $a t e r m o f f i b b o n a c c i s e r i e s .$ $b u t t h e r e a r e o t h e r n u m b e r s a l s o l i k e$ $233 - 13 t h t e r m - a p r i m e n u m b e r s o i t$ $d o e s n o t h a v e a f a c t o r w h i c h i s a f i b o n a c c i n u m b e r$
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