s=∫_0 ^( x) (√(1+(3t^2 +p)^2 ))dt = ? take p=1 for a special case.


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Question Number 55702 by ajfour last updated on 02/Mar/19

$s = \int_{0}^{x} \sqrt{1 + {(3 t^{2} + p)}^{2}} d t = ?$ $t a k e p = 1 f o r a s p e c i a l c a s e .$
Commented by rahul 19 last updated on 03/Mar/19

$I t h i n k f o r p = 1 y o u c a n s o l v e b y u s i n g$ $N e w t o n - L e i b n e i t z a n d t h e n i n t e g r a t e .$ $(A l t h o u g h l i t t l e l e n g t h y)!$
Commented by mr W last updated on 03/Mar/19

$i s t h i s n o t a n e l l i p i c i n t e g r a l w h i c h c a n$ $n o t b e s o l v e d i n e l e m e n t a r y f u n c t i o n s ?$
Commented by mr W last updated on 03/Mar/19

$n o! w e {c a n}^{'} t! i t i s n o t t o f i n d a v a l u e,$ $b u t t o f i n d a f u n c t i o n s (x) .$
Commented by maxmathsup by imad last updated on 03/Mar/19

$t h e r m a r k o f s i r m r w i s t r u e b e c a u s e s i s a f u n c t i o n o f x n o t a c o n s t a n t v a l u e . . .$
Commented by ajfour last updated on 03/Mar/19

$t h a n k s e v e r y o n e f o r c h e c k i n g$ $s u c h i s t h e c a s e .$
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