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Question Number 55737 by byaw last updated on 03/Mar/19

Commented by mr W last updated on 03/Mar/19

(i) p=(0.3)^4 =0.0081 (ii) p=(0.7)^4 =0.2401

$$\left({i}\right) \\ $$$${p}=\left(\mathrm{0}.\mathrm{3}\right)^{\mathrm{4}} =\mathrm{0}.\mathrm{0081} \\ $$$$\left({ii}\right) \\ $$$${p}=\left(\mathrm{0}.\mathrm{7}\right)^{\mathrm{4}} =\mathrm{0}.\mathrm{2401} \\ $$

Commented by byaw last updated on 03/Mar/19

Thank you very much

$${Thank}\:{you}\:{very}\:{much}\: \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 03/Mar/19

let (100n)transistor type A=30n type B=70n i)((30n_c_4 )/(100n_c_4 ))=(((30n!)/(4!(30n−4)!))/((100n!)/((100n−4)!4!)))=((30n!×(100n−4)!)/((30n−4)!×100n!)) =((30n×(30n−1)×(30n−2)(30n−3))/(100n×(100n−1)×(100n−2)(100n−3))) =(3/(10))×((30−(1/n))/(100−(1/n)))×((30−(2/n))/(100−(2/n)))×((30−(3/n))/(100−(3/n))) ≈(3/(10))×((30)/(100))×((30)/(100))×((30)/(100)) =((3/(10)))^4 pls check ii)for B type =((7/(10)))^4 pls check...

$${let}\:\left(\mathrm{100}{n}\right){transistor} \\ $$$${type}\:{A}=\mathrm{30}{n} \\ $$$${type}\:{B}=\mathrm{70}{n} \\ $$$$\left.{i}\right)\frac{\mathrm{30}{n}_{{c}_{\mathrm{4}} } }{\mathrm{100}{n}_{{c}_{\mathrm{4}} } }=\frac{\frac{\mathrm{30}{n}!}{\mathrm{4}!\left(\mathrm{30}{n}−\mathrm{4}\right)!}}{\frac{\mathrm{100}{n}!}{\left(\mathrm{100}{n}−\mathrm{4}\right)!\mathrm{4}!}}=\frac{\mathrm{30}{n}!×\left(\mathrm{100}{n}−\mathrm{4}\right)!}{\left(\mathrm{30}{n}−\mathrm{4}\right)!×\mathrm{100}{n}!} \\ $$$$=\frac{\mathrm{30}{n}×\left(\mathrm{30}{n}−\mathrm{1}\right)×\left(\mathrm{30}{n}−\mathrm{2}\right)\left(\mathrm{30}{n}−\mathrm{3}\right)}{\mathrm{100}{n}×\left(\mathrm{100}{n}−\mathrm{1}\right)×\left(\mathrm{100}{n}−\mathrm{2}\right)\left(\mathrm{100}{n}−\mathrm{3}\right)} \\ $$$$=\frac{\mathrm{3}}{\mathrm{10}}×\frac{\mathrm{30}−\frac{\mathrm{1}}{{n}}}{\mathrm{100}−\frac{\mathrm{1}}{{n}}}×\frac{\mathrm{30}−\frac{\mathrm{2}}{{n}}}{\mathrm{100}−\frac{\mathrm{2}}{{n}}}×\frac{\mathrm{30}−\frac{\mathrm{3}}{{n}}}{\mathrm{100}−\frac{\mathrm{3}}{{n}}} \\ $$$$\approx\frac{\mathrm{3}}{\mathrm{10}}×\frac{\mathrm{30}}{\mathrm{100}}×\frac{\mathrm{30}}{\mathrm{100}}×\frac{\mathrm{30}}{\mathrm{100}} \\ $$$$=\left(\frac{\mathrm{3}}{\mathrm{10}}\right)^{\mathrm{4}} {pls}\:{check} \\ $$$$\left.{ii}\right){for}\:{B}\:{type}\:=\left(\frac{\mathrm{7}}{\mathrm{10}}\right)^{\mathrm{4}} \: \\ $$$${pls}\:{check}... \\ $$

Commented by byaw last updated on 03/Mar/19

Thank you bro

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{bro} \\ $$

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