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Question Number 55805 by bshahid010@gmail.com last updated on 04/Mar/19

Commented by MJS last updated on 04/Mar/19

$$\mathrm{b}=0\Rightarrow \frac{a^2+b^2}{ab+1}=a^2$$$$b=a^3\Rightarrow \frac{a^2+b^2}{ab+1}=a^2$$$$\mathrm{but}{\mathrm{I}}^{\prime }\mathrm{m}\mathrm{not}\mathrm{sure}\mathrm{if}\mathrm{there}\mathrm{are}\mathrm{other}\mathrm{possible}$$$$\mathrm{values}\mathrm{for}b$$

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