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Question Number 55843 by gunawan last updated on 05/Mar/19

Consider the system of equations  a_1 x+b_1 y+c_1 z=0, a_2 x+b_2 y+c_2 z=0 ,  a_3 x+b_3 y+c_3 z=0  if   determinant ((a_1 ,b_1 ,c_1 ),(a_2 ,b_2 ,c_2 ),(a_3 ,b_3 ,c_3 )) = 0, then the system has

$$\mathrm{Consider}\:\mathrm{the}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equations} \\ $$$${a}_{\mathrm{1}} {x}+{b}_{\mathrm{1}} {y}+{c}_{\mathrm{1}} {z}=\mathrm{0},\:{a}_{\mathrm{2}} {x}+{b}_{\mathrm{2}} {y}+{c}_{\mathrm{2}} {z}=\mathrm{0}\:, \\ $$$${a}_{\mathrm{3}} {x}+{b}_{\mathrm{3}} {y}+{c}_{\mathrm{3}} {z}=\mathrm{0}\:\:\mathrm{if} \\ $$$$\begin{vmatrix}{{a}_{\mathrm{1}} }&{{b}_{\mathrm{1}} }&{{c}_{\mathrm{1}} }\\{{a}_{\mathrm{2}} }&{{b}_{\mathrm{2}} }&{{c}_{\mathrm{2}} }\\{{a}_{\mathrm{3}} }&{{b}_{\mathrm{3}} }&{{c}_{\mathrm{3}} }\end{vmatrix}\:=\:\mathrm{0},\:\mathrm{then}\:\mathrm{the}\:\mathrm{system}\:\mathrm{has} \\ $$

Commented by gunawan last updated on 05/Mar/19

What the answer is x=y=z=0 ?

$$\mathrm{What}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}\:{x}={y}={z}=\mathrm{0}\:? \\ $$

Answered by 121194 last updated on 05/Mar/19

the system was infinite solutions

$$\mathrm{the}\:\mathrm{system}\:\mathrm{was}\:\mathrm{infinite}\:\mathrm{solutions} \\ $$

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