Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 55889 by behi83417@gmail.com last updated on 05/Mar/19

     a=b^2 +bc+c^2        b=a^2 +ac+c^2        c=a^2 +ab+b^2      solve for :  a,  b,  c.

$$\:\:\:\:\:\boldsymbol{\mathrm{a}}=\boldsymbol{\mathrm{b}}^{\mathrm{2}} +\boldsymbol{\mathrm{bc}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{b}}=\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{ac}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\boldsymbol{\mathrm{c}}=\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{ab}}+\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\boldsymbol{\mathrm{a}},\:\:\boldsymbol{\mathrm{b}},\:\:\boldsymbol{\mathrm{c}}. \\ $$

Answered by MJS last updated on 05/Mar/19

a=b=c=0 ∨ a=b=c=(1/3)

$${a}={b}={c}=\mathrm{0}\:\vee\:{a}={b}={c}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com