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Question Number 55913 by peter frank last updated on 06/Mar/19
Answered by tanmay.chaudhury50@gmail.com last updated on 06/Mar/19
OA→=−2i+2j+3kOB→=2i−3j+kOC→=4i+5j+3kBC→=OC→−OB→=2i+8j+2kinquestionnovalueofforcealsodirectionnotgiven.assumingmagnetudeofforceFanddirectionOA→midpointofBandCisD(3,1,2)OD→=3i+j+2kBD→=OD→−OB→BD→=i+4j+kDC→=OC→−OD→DC→=i+4j+kworkdoneB→DthenD→CF(−2i+2j+3k).(i+4j+k)+F2(−2i+2j+3k).(i+4j+k)3F2(−2+8+3)27F2
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