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Question Number 55926 by MJS last updated on 06/Mar/19

Ancient Roman Number Magic:  take 5 matches or picks and form a roman 3                                          ∣∣∣_(−) ^(−)   now subtract 2 so that a little more than 3 is left

$$\mathrm{Ancient}\:\mathrm{Roman}\:\mathrm{Number}\:\mathrm{Magic}: \\ $$$$\mathrm{take}\:\mathrm{5}\:\mathrm{matches}\:\mathrm{or}\:\mathrm{picks}\:\mathrm{and}\:\mathrm{form}\:\mathrm{a}\:\mathrm{roman}\:\mathrm{3} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{−} {\overline {\mid\mid\mid}} \\ $$$$\mathrm{now}\:\mathrm{subtract}\:\mathrm{2}\:\mathrm{so}\:\mathrm{that}\:\mathrm{a}\:\mathrm{little}\:\mathrm{more}\:\mathrm{than}\:\mathrm{3}\:\mathrm{is}\:\mathrm{left} \\ $$

Answered by MJS last updated on 06/Mar/19

it′s easy: take away 2 matches:                                           ∣∣^(−)  ≈3.14>3  mathematicians′ joke...

$$\mathrm{it}'\mathrm{s}\:\mathrm{easy}:\:\mathrm{take}\:\mathrm{away}\:\mathrm{2}\:\mathrm{matches}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\overline {\mid\mid}\:\approx\mathrm{3}.\mathrm{14}>\mathrm{3} \\ $$$$\mathrm{mathematicians}'\:\mathrm{joke}... \\ $$

Commented by ajfour last updated on 06/Mar/19

Beautiful!

$${Beautiful}! \\ $$

Commented by MJS last updated on 06/Mar/19

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

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