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Question Number 56052 by mr W last updated on 09/Mar/19

$$Solvefollowingequationforx:$$$${\mathit{x}}^{{\mathit{x}}^{{\mathit{x}}^{\mathit{n}}}}=\mathit{n}withn\in \mathbb{N}$$

Answered by MJS last updated on 09/Mar/19

$$x=\sqrt[n]{n}$$$$\mathrm{is}\mathrm{at}\mathrm{least}\mathrm{one}\mathrm{solution}$$$$\mathrm{this}\mathrm{seems}\mathrm{true}\mathrm{for}n\in \mathbb{C}\mathrm{\setminus }\left\{0\right\}$$

Commented by mr W last updated on 09/Mar/19

$$thankssir!$$

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