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Question Number 56052 by mr W last updated on 09/Mar/19

Solve following equation for x:  x^x^x^n   =n with n∈N

$${Solve}\:{following}\:{equation}\:{for}\:{x}: \\ $$$$\boldsymbol{{x}}^{\boldsymbol{{x}}^{\boldsymbol{{x}}^{\boldsymbol{{n}}} } } =\boldsymbol{{n}}\:{with}\:{n}\in\mathbb{N} \\ $$

Answered by MJS last updated on 09/Mar/19

x=(n)^(1/n)   is at least one solution  this seems true for n∈C\{0}

$${x}=\sqrt[{{n}}]{{n}} \\ $$$$\mathrm{is}\:\mathrm{at}\:\mathrm{least}\:\mathrm{one}\:\mathrm{solution} \\ $$$$\mathrm{this}\:\mathrm{seems}\:\mathrm{true}\:\mathrm{for}\:{n}\in\mathbb{C}\backslash\left\{\mathrm{0}\right\} \\ $$

Commented by mr W last updated on 09/Mar/19

thanks sir!

$${thanks}\:{sir}! \\ $$

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