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Question Number 56165 by Tawa1 last updated on 11/Mar/19

Answered by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19

$$A=6cos{36}^{0}i+6sin{36}^{o}j$$$$B=-7i$$$$A+B=(6cos{36}^o-7)i+6sin{36}^{0}j$$$$A-B=(6cos36+7)i+6sin36j$$$$\mid A+B{\mid }^{\mid }=\sqrt{{(6cos{36}^0-7)}^2+{\left(6sin{36}^o\right)}^2}$$$$=\sqrt{6^2+7^2-2\times 6\times 7cos{36}^o}$$$$\mid A-B\mid =\sqrt{6^2+7^2+2\times 6\times 7cos{36}_{}^o}$$

Commented by Tawa1 last updated on 11/Mar/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}$$

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