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Question Number 56336 by otchereabdullai@gmail.com last updated on 14/Mar/19

make r the subject of P=(1+(r/(100)))^t

$$\mathrm{make}\:\:\mathrm{r}\:\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\:\: \\ $$$$\mathrm{P}=\left(\mathrm{1}+\frac{\mathrm{r}}{\mathrm{100}}\right)^{\mathrm{t}} \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 14/Mar/19

question not clear.... p=(1+(r/(100)))^t p^(1/t) =1+(r/(100)) r=100(p^(1/t) āˆ’1)

$${question}\:{not}\:{clear}.... \\ $$$${p}=\left(\mathrm{1}+\frac{{r}}{\mathrm{100}}\right)^{{t}} \\ $$$${p}^{\frac{\mathrm{1}}{{t}}} =\mathrm{1}+\frac{{r}}{\mathrm{100}} \\ $$$${r}=\mathrm{100}\left({p}^{\frac{\mathrm{1}}{{t}}} āˆ’\mathrm{1}\right) \\ $$

Commented by otchereabdullai@gmail.com last updated on 14/Mar/19

thank you prof am much greatful

$$\mathrm{thank}\:\:\mathrm{you}\:\mathrm{prof}\:\mathrm{am}\:\mathrm{much}\:\mathrm{greatful} \\ $$

Commented by otchereabdullai@gmail.com last updated on 14/Mar/19

prof how did get the p^(1/t) i want to understand

$$\mathrm{prof}\:\mathrm{how}\:\mathrm{did}\:\mathrm{get}\:\mathrm{the}\:\mathrm{p}^{\frac{\mathrm{1}}{\mathrm{t}}} \:\mathrm{i}\:\mathrm{want}\:\mathrm{to}\: \\ $$$$\mathrm{understand} \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 14/Mar/19

supose x^a =b now to eliminate a from the power of x x^a =b (x^a )^(1/a) =(b)^(1/a) x^(aƗ(1/a)) =b^(1/a) x=b^(1/a)

$${supose} \\ $$$${x}^{{a}} ={b} \\ $$$${now}\:{to}\:{eliminate}\:\boldsymbol{{a}}\:{from}\:{the}\:{power}\:{of}\:{x} \\ $$$$\boldsymbol{{x}}^{\boldsymbol{{a}}} =\boldsymbol{{b}} \\ $$$$\left(\boldsymbol{{x}}^{\boldsymbol{{a}}} \right)^{\frac{\mathrm{1}}{\boldsymbol{{a}}}} =\left(\boldsymbol{{b}}\right)^{\frac{\mathrm{1}}{\boldsymbol{{a}}}} \\ $$$$\boldsymbol{{x}}^{\boldsymbol{{a}}Ɨ\frac{\mathrm{1}}{\boldsymbol{{a}}}} =\boldsymbol{{b}}^{\frac{\mathrm{1}}{\boldsymbol{{a}}}} \\ $$$$\boldsymbol{{x}}=\boldsymbol{{b}}^{\frac{\mathrm{1}}{\boldsymbol{{a}}}} \\ $$

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