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Question Number 56523 by arvinddayama02@gmail.com last updated on 18/Mar/19
∫x3x3+2dx=?
Commented by MJS last updated on 18/Mar/19
itseemsimpossibletosolve
possiblearethese:∫x3x2+2dx∫x23x3+2dx(bothareeasy)and,harder:∫x3x3+23dx
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