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Question Number 56523 by arvinddayama02@gmail.com last updated on 18/Mar/19

∫x(√(3x^3 +2)) dx=?

x3x3+2dx=?

Commented by MJS last updated on 18/Mar/19

it seems impossible to solve

itseemsimpossibletosolve

Commented by MJS last updated on 18/Mar/19

possible are these:  ∫x(√(3x^2 +2))dx  ∫x^2 (√(3x^3 +2))dx  (both are easy)  and, harder:  ∫x((3x^3 +2))^(1/3) dx

possiblearethese:x3x2+2dxx23x3+2dx(bothareeasy)and,harder:x3x3+23dx

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