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Question Number 56575 by Sr@2004 last updated on 18/Mar/19

Commented by Sr@2004 last updated on 18/Mar/19

$p l e a s e s o l v e 12 e r 1 n o .$
Commented by Sr@2004 last updated on 20/Mar/19

	Answered by tanmay.chaudhury50@gmail.com last updated on 18/Mar/19

	$u_{n} = {s i n}^{n} α + {c o s}^{n} α$ $u_{4} = {s i n}^{4} α + {c o s}^{4} α$ $= {({s i n}^{2} + {c o s}^{2} α)}^{2} - 2 {s i n}^{2} α {c o s}^{2} α$ $6 u_{4} = 6 - 12 {s i n}^{2} α {c o s}^{2} α$ $p + +$ $u_{6} = {s i n}^{6} α + {c o s}^{6} α$ $= {({s i n}^{2} + {c o s}^{2} α)}^{3} - 3 {s i n}^{2} {c o s}^{2} α ({s i n}^{2} α + {c o s}^{2} α)$ $= 1 - 3 {s i n}^{2} α {c o s}^{2} α$ $4 u_{6} = 4 - 12 {s i n}^{2} α {c o s}^{2} α$ $6 u_{4} - 4 u_{6}$ $= 6 - 12 {s i n}^{2} α {c o}^{2} α - 4 + 12 {s i n}^{} α {c o s}^{2} α$ $s o a n s w e t i s 6 - 4 = 2$
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