Question and Answers Forum

All Questions      Topic List

Permutation and Combination Questions

Previous in All Question      Next in All Question      

Previous in Permutation and Combination      Next in Permutation and Combination      

Question Number 56624 by pieroo last updated on 19/Mar/19

$$\mathrm{How}\mathrm{many}\mathrm{numbers}\mathrm{greater}\mathrm{than}2000$$$$\mathrm{can}\mathrm{be}\mathrm{formed}\mathrm{using}\mathrm{the}\mathrm{digits}1,3,4,5,6?$$$$\mathrm{how}\mathrm{many}\mathrm{of}\mathrm{these}\mathrm{will}\mathrm{be}\mathrm{even}?$$$$\mathrm{repetition}\mathrm{not}\mathrm{allowed}.$$

Commented by pieroo last updated on 19/Mar/19

$$\mathrm{repetition}\mathrm{not}\mathrm{allowed}.\mathrm{Thanks}.$$

Commented by Kunal12588 last updated on 19/Mar/19

$$repetionisallowedornot?$$$$needed4or5orgreaterdigitno?$$$$ifcountingeverynumbergreaterthan2000$$$$formedusing1,3,4,5,6.answer\mathrm{\infty }$$$$$$$$counting4and5digitnumber,repetion$$$$notallowed.$$$$4\times 4!+5!=4!\left(9\right)=24\times 9=216ans$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com