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Question Number 56696 by Tawa1 last updated on 21/Mar/19

$$\mathrm{Find}\mathrm{the}\mathrm{perpendicular}\mathrm{distance}\mathrm{from}(1,7,1)\mathrm{to}3\mathrm{x}-2\mathrm{y}+2\mathrm{z}=6$$

Commented by mr W last updated on 21/Mar/19

$$d=\frac{\mid 3\times 1-2\times 7+2\times 1-6\mid }{\sqrt{3^2+{(-2)}^2+2^2}}=\frac{15}{\sqrt{17}}$$

Commented by Tawa1 last updated on 22/Mar/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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